TOPOLOGY · CIRCULAR
TX: HELMHOLTZ
RX: DTC
CLOSED-FORM SOLVER

Circular Helmholtz → DTC

A circular Helmholtz transmitter driving a flat planar-spiral (DTC) receiver. This pairing suits designs where the transmitter can surround the working volume but the receiver must stay thin.

01. · Run this geometry

The simulator computes the field from the Biot–Savart law and the mutual inductance from the Neumann double integral, then reports the coupling coefficient k for the geometry you enter. Nothing is meshed and nothing is fitted, so the result is reproducible to the digit.

02. · When this topology is the right choice

Use it for

  • Charging a thin device inside an instrumented volume or fixture
  • Implant and sensor work where receiver thickness is the binding constraint
  • Cases needing misalignment tolerance from the transmitter side

Watch out for

  • A small planar receiver intercepts only part of the transmitter flux, so k is usually well below a matched pair
  • Receiver tilt costs more coupling here than lateral offset does
03. · The other seven topologies

Run your geometry.

Frequently asked questions

How is mutual inductance calculated for a circular Helmholtz to DTC pair?

AirInduct evaluates the Neumann double integral between every transmitter turn and every receiver turn, then sums the contributions. Circular turns are evaluated with complete elliptic integrals (K and E), which is why the circular cases are the fastest and the most numerically exact in the solver. Because this is a closed-form evaluation rather than a meshed field solve, the same geometry always returns the same number and there is no discretisation error to tune away.

What coupling coefficient should I expect from this topology?

There is no single figure — k depends on the radii, turn counts, separation and alignment you choose, and it falls off steeply with distance. That is precisely why this page links to the simulator rather than quoting a number: enter your geometry and read k directly. As a rough orientation, closely spaced pairs of similar size can reach k above 0.5, while a gap comparable to the coil radius typically drops k below 0.1.

Do I need to install anything?

No. The solver runs from the browser and the free tier covers individual research and coursework use. Desktop and mobile builds run the identical kernels if you prefer a local install.

Is this accurate enough to replace a full-wave FEM tool?

For inductive WPT in the magnetostatic regime — coils small relative to a wavelength, no dominant ferrite or lossy material in the field volume — the closed-form result is exact, not approximate. If your design depends on shielding, ferrite loading, strong proximity effects in litz bundles, or radiative behaviour, a full-wave or FEM tool is the right instrument and we will tell you so.